Question

$2^3(5^0+3^{2x})=8\frac{8}{27}$

Answer 1

$2^3(5^0+3^{2x})=8\frac{8}{27}$

$8$($1$$+$$3^{2x}$)$=$$\frac{27\times 8+8}{27}$

$8$+$8$$\times$$3^{2x}$$=$$\frac{224}{27}$

$8$$\times$$3^{2x}$$=$$\frac{224}{27}$$-$$8$

$8$$\times$$3^{2x}$$=$$\frac{224-216}{27}$

$8$$\times$$3^{2x}$$=$$\frac{8}{27}$

$3^{2x}$$=$ $3^{-3}$

since bases are equal powers can be eqaulize

$2x$=$-3$

$x$$=$$\frac{-3}{2}$