The correct option is A 5 If you are already standing on ( 2) on the nbsp;number line and you are told to move 3 places to your left, you would be at ( 5). ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VII

Mathematics

Addition of Negative Numbers (-X-Y = -(X+Y))

-2-3=?

Question

$- 2 - 3 = ?$

$- 5$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
$- 5$

If you are already standing on ( $- 2$ ) on the number line and you are told to move $3$ places to your left, you would be at ( $- 5$ ).

$∴$ - 2 - 3 = - 5

Suggest Corrections

Similar questions

Q. If a =

2^{3} \times 3^{3} \times 7^{2}

and

b = 2^{2} \times 3^{2} \times 5^{3},

which is true?

3 y \sqrt{2} = 144 \sqrt{3} = 1.732 f i n d t h e v a l u e o f \frac{4}{3 \sqrt{3} - 2 \sqrt{2}} + \frac{3}{3 \sqrt{3} + 2 \sqrt{2}}

Q. Simplify:

\frac{3 \sqrt{2} - 2 \sqrt{3}}{3 \sqrt{2} + 2 \sqrt{3}} + \frac{\sqrt{8}}{\sqrt{3} - \sqrt{2}}

\frac{1^{3} + 2^{3} + 3^{3} + 4^{3} + . . . . . . . {.12}^{3}}{1^{2} + 2^{2} + 3^{2} + 4^{2} + . . . . . {.12}^{2}} =

1^{3} + 1^{2} + 1 + 2^{3} + 2^{2} + 2 + 3^{3} + 3^{2} + 3 + . . . 3 n

terms

=

Join BYJU'S Learning Program

−2−3= ?

The correct option is A −5 If you are already standing on (−2) on the number line and you are told to move 3 places to your left, you would be at (−5). ∴ - 2 - 3 = - 5

$- 2 - 3 = ?$

The correct option is A
$- 5$

If you are already standing on ( $- 2$ ) on the number line and you are told to move $3$ places to your left, you would be at ( $- 5$ ).

$∴$ - 2 - 3 = - 5