2, 3, 5, 7, 11, ?, 17

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Solution

The correct option is B 13
Clearly, the given series consists of prime numbers starting from 2. So, the missing term is the prime number after 11, which is 13.

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Similar questions

Add (i) $(2 \sqrt{3} - 5 \sqrt{2}) a n d (\sqrt{3} + 2 \sqrt{2})$

(ii) $(2 \sqrt{2} + 5 \sqrt{3} - 7 \sqrt{5}) a n d (3 \sqrt{3} - \sqrt{2} + \sqrt{5})$

(iii) $(\frac{2}{3} \sqrt{7} - \frac{1}{2} \sqrt{2} + 6 \sqrt{11}) a n d (\frac{1}{3} \sqrt{7} + \frac{3}{2} \sqrt{2} - \sqrt{11})$

(i) \frac{5 + 2 \sqrt{3}}{7 + 4 \sqrt{3}} = a - 6 \sqrt{3}

(i i) \frac{3 - \sqrt{5}}{3 + 2 \sqrt{5}} = a \sqrt{5} - \frac{19}{11}

(i i i) \frac{\sqrt{2} + \sqrt{3}}{3 \sqrt{2} - 2 \sqrt{3}} = 2 - b \sqrt{6}

(i v) \frac{7 + \sqrt{5}}{7 - \sqrt{5}} - \frac{7 - \sqrt{5}}{7 + \sqrt{5}} = a + \frac{7}{11} \sqrt{5} b

A = {2, 3, 5, 7, 11, 13}

B = {5, 7, 9, 11, 15}

U = {2, 3, 5, 7, 9, 11, 13, 15}

5 \times 6 \times 7 \times 11 - 2 \times 3 \times 7 \times 11

Simplify the following expressions :

(i) $(11 + \sqrt{11}) (11 - \sqrt{11})$

(ii) $(5 + \sqrt{7}) (5 - \sqrt{7})$

(iii) $(\sqrt{8} - \sqrt{2}) (\sqrt{8} + \sqrt{2})$

(iv) $(3 + \sqrt{3}) (3 - \sqrt{3})$

(v) $(\sqrt{5} - \sqrt{2}) (\sqrt{5} + \sqrt{2})$

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