2, 3, 9, when used once, can be arranged to form _______ distinct 3-digit numbers.

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Solution

The correct option is B 6

The given three digits can be arranged to form 6 distinct 3-digit numbers. They are $932, 923, 239, 293, 329, 392$ .
.i.e, Arrangement of 3 distinct digit in $3! = 3 \times 2 \times 1 = 6$ ways.

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