Question

$(2-3b+c{)}^2$ =$4+9b^2+c^2-12b-6bc+4c$. Is it true? If true enter 1 else 0.

Answer 1

Now,

$(2-3b+c{)}^2$

$=2^2+(-3b{)}^2+c^2+\mathrm{2.2.}(-3b)+\mathrm{2.2.}c+2.(-3b).c$

$=4+9b^2+c^2-12b-6bc+4c$.

So the given statement is true.

Hence the correct answer is $1$.