2, 3 - dibromobutane can be converted to 2 - butyne in a two -step reaction using

(i) HCI and (ii) NaH

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(i) alcoholic KOH and (ii)

N a N H_{2}

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(i) Na and (ii) NaOH

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(i)

B r_{2}

and (ii) NaH

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Solution

The correct option is B (i) alcoholic KOH and (ii) $N a N H_{2}$
$C H_{3} - C H B r - C H B r - C H_{3} a l c K O H / Δ - ------ \to C H_{3} - C H = C B r - C H_{3} N a N H_{2} (N H_{3}) - -------- \to C H_{3} - C \equiv C - C H_{3}$

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Similar questions

S t a t e m e n t

B r_{2}

It is given that when (±)-2,3-dibromobutane reacts with $K O H$ , some of the products formed are:

Explain via mechanism and then choose the correct ones from the following.

Monosubstitution of (2S,3S)-2,3-dibromobutane using $O H^{-}$ yields a mixture of products.
Monosubstitution of (2S,3S)-2,3-dibromobutane using $O H^{-}$ yields a single major product.
Monosubstitution of (2R,3R)-2,3-dibromobutane using $O H^{-}$ yields a mixture of products.
Monosubstitution of (2S,3S)-2,3-dibromobutane using $O H^{-}$ yields a mixture of products.

B r_{2}

C C l_{4}

B r_{2}

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