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Exponents with Unlike Bases and Same Exponent

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Question

$2^{3} \times 3^{3}$
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Solution

$2^{3} \times 3^{3} = (2 \times 3)^{3} = 6^{3} = 216$

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Q. 5 6 12 19 : 22 23 33 44 :: ? : 16 24 23 33

1^{3} + 2^{3} + 3^{3} + . . . . . . + n^{3} = {(\frac{n (n + 1)}{2})}^{2}

1^{3} + 2^{3} + 3^{3} + . . . . . . + 21^{3}

2^{3} \times 3^{3} \times 7^{2}

b = 2^{2} \times 3^{2} \times 5^{3},

Solve: $3^{3} - 2^{3}$

5)^{3} + (- 2)^{3} + (- 3)^{3} =

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Exponents with Unlike Bases and Same Exponent

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