2-3-7-3 is equal to-14-3-2-7-3-1-14-3-2-7-3

The correct options are A 14^3 B (2×7)^3By using law of exponents: a^m× b^m=(ab)^m nbsp; here a and b are base, and m is the exponent. nbsp;∴ 2^3×7^3=(2×7) ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VII

Mathematics

Exponent Numbers with Different Base and Same Power

2^3×7^3 is eq...

Question

$2^{3} \times 7^{3}$ is equal to____.

14^{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(2 \times 7)^{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(\frac{1}{14})^{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(2 \times 7)^{- 3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct options are
A $14^{3}$
B $(2 \times 7)^{3}$
By using law of exponents:
$a^{m} \times b^{m} = (a b)^{m}$
$here a and b are base, and m is the exponent$ .
$∴ 2^{3} \times 7^{3} = (2 \times 7)^{3}$
$= 14^{3}$

Suggest Corrections

Similar questions

Q. 6 boys and 6 girls sit in a row at random. The probability that all the girls sit together is

(a)

\frac{1}{432}

(b)

\frac{12}{431}

(c)

\frac{1}{132}

(d) None of these

Q. Solve:

(i)

\frac{5}{12} + \frac{1}{12}

(ii)

\frac{3}{15} + \frac{7}{15}

(iii)

\frac{3}{22} + \frac{7}{22}

(iv)

\frac{1}{4} + \frac{0}{4}

(v)

\frac{4}{13} + \frac{2}{13} + \frac{1}{13}

(vi)

\frac{0}{15} + \frac{2}{15} + \frac{1}{15}

(vii)

\frac{7}{31} - \frac{4}{31} + \frac{9}{31}

(viii)

3 \frac{2}{7} + \frac{1}{7} - 2 \frac{3}{7}

(ix)

2 \frac{1}{3} - 1 \frac{2}{3} + 4 \frac{1}{3}

(x)

1 - \frac{2}{3} + \frac{7}{3}

(xi)

\frac{16}{7} - \frac{5}{7} + \frac{9}{7}

Q. Divide the following by Paravartya yojayet method:

1432 \div 88

2^{3} \times 7^{3}

is equal to____.

Q. Write the following numbers in ascending order.
1432, 1425, 1456, 1496 and 1498

Join BYJU'S Learning Program

23×73 is equal to____.

The correct options are A 143 B (2×7)3By using law of exponents: am× bm=(ab)m here a and b are base, and m is the exponent. ∴23×73=(2×7)3 =143

$2^{3} \times 7^{3}$ is equal to____.

The correct options are
A $14^{3}$
B $(2 \times 7)^{3}$
By using law of exponents:
$a^{m} \times b^{m} = (a b)^{m}$
$here a and b are base, and m is the exponent$ .
$∴ 2^{3} \times 7^{3} = (2 \times 7)^{3}$
$= 14^{3}$