The correct option is C 100 By BODMAS, #160; #160; 2(34+66) (23+77) = 2(34+66) 100 = 2(100) 100 =200 100 =100 ...

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nth Term of A.P

234+66-23+77=

Question

$2 (34 + 66) - (23 + 77) =$

200

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56

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100

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50

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Solution

The correct option is C $100$
By BODMAS,

$2 (34 + 66) - (23 + 77)$
$= 2 (34 + 66) - 100$
$= 2 (100) - 100$
$= 200 - 100$
$= 100$

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Similar questions

Class interval	$22 - 33$	$33 - 44$	$44 - 55$	$55 - 66$	$66 - 77$	$77 - 88$	$88 - 99$
Frequency	$23$	$45$	$67$	$89$	$100$	$123$	$20$

Class	$0 - 100$	$100 - 200$	$200 - 300$	$300 - 400$	$400 - 500$	$500 - 600$
Frequency	$64$	$62$	$77$	$62$	$66$	$54$

Compute the following difference

$(228 \times 172) - (234 \times 66)$

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