The correct option is B FalseBy the Laws of Exponents,( a)^even number=a^even number ⇒( 2)^4=2^4=2×2×2×2=16 ( 3)^4=3^4=3×3×3×3=81 1681. So it is false. ...

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Byju's Answer

Standard VII

Mathematics

Terms with Negative Base

-24>-34

Question

$(- 2)^{4} > (- 3)^{4}$

True

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False

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Solution

The correct option is B False
By the Laws of Exponents, $(- a)^{e v e n n u m b e r} = a^{e v e n n u m b e r}$
$\Rightarrow$ $(- 2)^{4} = 2^{4} = 2 \times 2 \times 2 \times 2 = 16$
$(- 3)^{4} = 3^{4} = 3 \times 3 \times 3 \times 3 = 81$
$16 ≯ 81$ . So it is false.

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Similar questions

\int \frac{(2^{4} + 3^{4})}{2^{4} 3^{4}} d x

Q. (− 29) + 5 is equal to

(a) 24 (b) 34 (c) − 34 (d) − 24

{(- 2)}^{4} \times {(3)}^{4}

= .

{(- 2)}^{4} \times {(3)}^{4}

= .

Q. Simplify:

2^{4} \times 3^{4}

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(−2)4>(−3)4

The correct option is B FalseBy the Laws of Exponents,(−a)evennumber=aevennumber ⇒(−2)4=24=2×2×2×2=16 (−3)4=34=3×3×3×3=81 16≯81. So it is false.

$(- 2)^{4} > (- 3)^{4}$

The correct option is B False
By the Laws of Exponents, $(- a)^{e v e n n u m b e r} = a^{e v e n n u m b e r}$
$\Rightarrow$ $(- 2)^{4} = 2^{4} = 2 \times 2 \times 2 \times 2 = 16$
$(- 3)^{4} = 3^{4} = 3 \times 3 \times 3 \times 3 = 81$
$16 ≯ 81$ . So it is false.