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Question

2.5F of electricity are passed through a CuSO4 solution. The number of gm equivalent of Cu deposited on anode is:

A
Zero
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B
2.5
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C
1.25
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D
63.5
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Solution

The correct option is D 63.5

We know that

W=ZIt

Where,

W = amount of substance deposited

Z = electrochemical equivalent

I = amount of current

t = time

It=Q=2F (given)

Z=atomic massnF=63.52F

Hence,

W=ZIt

W=63.52F×2F=63.5 g


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