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Extraction of Copper

2.5 g sample ...

Question

$2.5$ g sample of copper is dissolved in excess of $H_{2} S O_{4}$ to prepare $100$ ml of $0.02 M C u S O_{4} (a q)$ . $10$ ml of $0.02 M$ solution of $C u S O_{4} (a q)$ is mixed with excess of $K I$ to show the following changes:

$C u S O_{4} + 2 K I ⟶ K_{2} S O_{4} + C u I_{2}$
$2 C u I_{2} ⟶ C u_{2} I_{2} + I_{2}$

The liberated iodine is titrated with hypo ( $N a_{2} S_{2} O_{3}$ ) which requires $V$ ml of $0.1 M$ hypo solution for its complete reduction.

The color of the solution developed during the addition of $K I$ to $C u S O_{4}$ solution is :

A

Violet due to dissolution of liberated

I_{2}

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B

Brownish yellow due to dissolution of liberated

I_{2}

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C

Red due to the formation of

C u I_{2}

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D

Brown due to the formation of

C u_{2} I_{2}

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Solution

The correct option is B Brownish yellow due to dissolution of liberated $I_{2}$
Reaction:
$C u S O_{4} + 2 K I ⟶ K_{2} S O_{4} + C u I_{2}$
$2 C u I_{2} ⟶ C u_{2} I_{2} + I_{2}$
brownish yellow color

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Similar questions

2.5

g sample of copper is dissolved in excess of

H_{2} S O_{4}

100

0.02 M C u S O_{4} (a q)

10

0.02 M

C u S O_{4} (a q)

is mixed with excess of

K I

to show the following changes:

C u S O_{4} + 2 K I ⟶ K_{2} S O_{4} + C u I_{2}

2 C u I_{2} ⟶ C u_{2} I_{2} + I_{2}

The liberated iodine is titrated with hypo (

N a_{2} S_{2} O_{3}

) which requires

V

0.1 M

hypo solution for its complete reduction.The amount of

I_{2}

liberated in the reaction of

10

0.02 M

solution with excess

K I

2.5

g sample of copper is dissolved in excess of

H_{2} S O_{4}

100

0.02 M C u S O_{4} (a q)

10

0.02 M

C u S O_{4} (a q)

is mixed with excess of

K I

to show the following changes:

C u S O_{4} + 2 K I ⟶ K_{2} S O_{4} + C u I_{2}

2 C u I_{2} ⟶ C u_{2} I_{2} + I_{2}

The liberated iodine is titrated with hypo (

N a_{2} S_{2} O_{3}

) which requires

V

0.1 M

hypo solution for its complete reduction.

V

) of hypo required is:

2.5

g sample of copper is dissolved in excess of

H_{2} S O_{4}

100

0.02 M C u S O_{4} (a q)

10

0.02 M

C u S O_{4} (a q)

is mixed with excess of

K I

to show the following changes:

C u S O_{4} + 2 K I ⟶ K_{2} S O_{4} + C u I_{2}

2 C u I_{2} ⟶ C u_{2} I_{2} + I_{2}

The liberated iodine is titrated with hypo (

N a_{2} S_{2} O_{3}

) which requires

V

0.1 M

hypo solution for its complete reduction.

Percentage of purity of sample is:

Q. In an iodometric estimation, the following reactions occur

2 C u^{2 +} + 4 I^{-} \to C u_{2} I_{2} + I_{2}; I_{2} + 2 N a_{2} S_{2} O_{3} \to 2 N a I + N a_{2} S_{4} O_{6}

0.12 m o l e

C u S O_{4}

was added to excess of

K I

solution and the liberated iodine required

120 m L

of hypo. The molarity of hypo solution was:

638.0

C u S O_{4}

solution is titrated with excess of

0.2 M

K I

solution. The liberated

I_{2}

400

1.0 M

N a_{2} S_{2} O_{3}

for complete reaction. The percentage purity of

C u S O_{4}

in the sample is:

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