$2, 6, 14, 11, 15, 23, 20, 24,$ ____________, $29$ .

31

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29

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28

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32

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Solution

The correct option is C $32$
The series is as follows.

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\frac{2^{30} + 2^{29} + 2^{28}}{2^{31} + 2^{30} - 2^{29}}

\frac{2^{30} + 2^{29} + 2^{28}}{2^{31} + 2^{30} - 2^{29}} = \frac{7}{10}

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