2, 6, 18, 54, 162.....what is the nth term of the GP?

(3)^{n - 1}

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2 (3)^{n - 1}

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2 (3)^{n + 1}

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2 (3)^{n}

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Solution

The correct option is B $2 (3)^{n - 1}$
From given GP, we have $a = 2,$ common ratio , $r = 3$
We know the formula for nth term,
$a_{n} = a r^{n - 1}$
$a_{n} = 2 (3)^{n - 1}$

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