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Standard XII

Chemistry

Charles' Law

2.650 g of an...

Question

$2.650$ g of anhydrous sodium carbonate are dissolved in water and the solution made up to $500$ mL. On titration, $50$ mL of this solution neutralised $50$ mL of a solution of sulphuric acid. How much water should be added to $450$ mL of this acid as to make it exactly $N / 12$ ?

445

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395

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90

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225

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Solution

The correct option is D $90$ mL

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Similar questions

30 m L

N / 10 H C l

is required to neutralise

50 m L

of a sodium carbonate solution. How many

m L

of water must be added to

30 m L

of this solution so that the solution obtained may have a concentration equal to

N / 50

Q. One

g m

of impure sodium carbonate is dissolved in water and the solution is made up to

250 m l

. To

50 m l

of this made up solution,

50 m l

0.1 N

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is added and the mixture, after shaking well required

10 m l

0.16 N - N a O H

solution for complete titration.

Calculate the

%

purity of the sample:

1.575 g

of oxalic acid

(C O O H)_{2} \cdot x H_{2} O

are dissolved in water and the volume made up to

250 m L

. On titration

16.68 m L

of this solution requires

26 m L

\frac{N}{15} N a O H

solution for complete neutralisation. Calculate

x

30.0 mL of the given $H C l$ solution requires 20.0 mL of 0.1 M sodium carbonate solution for complete neutralisation. What is the volume of this $H C l$ solution required to neutralise 30.0 mL of 0.2 M $N a O H$ solution?

Q. In a sample of sodium carbonate some sodium sulphate is also mixed.

1.25 g

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250 m L

25 m L

of this solution neutralises

20 m L

\frac{N}{10}

sulphuric acid. Calculate the percentage of sodium carbonate in the sample.

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2.650 g of anhydrous sodium carbonate are dissolved in water and the solution made up to 500 mL. On titration, 50 mL of this solution neutralised 50 mL of a solution of sulphuric acid. How much water should be added to 450 mL of this acid as to make it exactly N/12?

The correct option is D 90 mL

$2.650$ g of anhydrous sodium carbonate are dissolved in water and the solution made up to $500$ mL. On titration, $50$ mL of this solution neutralised $50$ mL of a solution of sulphuric acid. How much water should be added to $450$ mL of this acid as to make it exactly $N / 12$ ?

The correct option is D $90$ mL