2.76 g of silver carbonate on being strongly heated yield a residue weighing:

2.16 g

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2.48 g

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2.64 g

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2.32 g

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Solution

The correct option is B 2.16 g
$A g_{2} C O_{3} (s) \to 2 A g (s) + C O_{2} (g) + \frac{1}{2} O_{2} (g)$

Molecular Weight of $A g_{2} C O_{3} = 276 g$

And, molecular weight of $A g = 2 \times 108 = 216 g$

276 g of $A g_{2} C O_{3}$ give 216 g $A g$ .

Therefore, 2.76 g of $A g_{2} C O_{3}$ on heating will give $\frac{216}{276} \times 2.76 g = 2.16 g A g$ as residue.

Hence, option A is correct.

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Similar questions

2.76 g

2.76

2.76g of silver carbonate (at mass of Ag = 108) on being heated strongly yields a residue

2.76 g

A g = 108 g/mol

A g_{2} C O_{3} Δ - \to 2 A g + C O_{2} + \frac{1}{2} O_{2}

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