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Question

2.82 g of glucose is dissolved in 30 g of water. The mole fraction of glucose in the solution is:

A
0.01
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B
0.99
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C
0.52
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D
1.66
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Solution

The correct option is A 0.01
Solution contains glucose C6H12O6 and water
Molar mass of glucose = 180 g
Molar mass of water= 18 g
mole fraction of glucose = moles of glucose/(moles of gluocose+moles of water)
moles of gluocose, n=mass/molar mass=2.82/180=0.016
moles of water, n=mass/molar mass=30/18=1.67
mole fraction of glucose =0.016/(0.016+1.67)=0.00950.01
Hence, option A is correct.

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