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Byju's Answer
Standard XII
Chemistry
Concentration Terms
2.82 g of glu...
Question
2.82
g
of glucose is dissolved in
30
g
of water. The mole fraction of glucose in the solution is:
A
0.01
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B
0.99
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C
0.52
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D
1.66
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Solution
The correct option is
A
0.01
Solution contains glucose
C
6
H
12
O
6
and water
Molar mass of glucose = 180 g
Molar mass of water= 18 g
mole fraction of glucose = moles of glucose/(moles of gluocose+moles of water)
moles of gluocose, n=mass/molar mass=
2.82
/
180
=
0.016
moles of water, n=mass/molar mass
=
30
/
18
=
1.67
mole fraction of glucose
=
0.016
/
(
0.016
+
1.67
)
=
0.0095
≈
0.01
Hence, option
A
is correct.
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