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Question

2) A stone is dropped from the window of a bus at 60km/hr.if the window is 1.96m high,find the distance along the track which the stone moves before striking the ground.


Solution

Since, the stone is dropped, its initial horizontal velocity is equal to the velocity og the bus which is, ux = 60 km/h = 16.67 m/s Its initial vertical velocity is, u y = 0 The height through which the stone falls is, h = 1.96 m Using, S = ut + ½ at 2 => 1.96 = 0 + ½ (9.8)(t 2 ) => t = 0.63 s Horizontal distance moved by the stone in this time is, X = u x t = (16.67)(0.63) = 10.5 m The path of the stone can be found as follows: X = u x t = 16.67t Y = u y t + ½ at 2 = (1/2)(9.8)t 2 = 4.9t 2

Physics

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