2- a triangle having a perimeter 56 and its side are 2x, 2x+3 and 2x+5. Find the respective lengths of the sides of the triangle.

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Solution

Dear student,

$G i v e n : s i d e s o f t r i a n g l e a r e 2 x, 2 x + 3, 2 x + 5 a n d p e r i m e t e r i s 56 W e k n o w, P e r i m e t e r = s u m o f a l l s i d e s \Rightarrow 56 = 2 x + 2 x + 3 + 2 x + 5 \Rightarrow 56 = 6 x + 8 \Rightarrow 6 x = 56 - 8 = 48 \Rightarrow x = \frac{48}{6} = 8 t h e r e f o r e t h e l e n g t h o f s i d e s a r e 2 x = 2 \times 8 = 16 2 x + 3 = 2 \times 8 + 3 = 19 2 x + 5 = 2 \times 8 + 5 = 21$
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