2b c cos A-c a cos B-a b cos C-A- abcB- a2-b2-c2C- a2-b2-c2D- 2 abc

The correct option is B a2+b2+c2 ...

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Cosine Rule

2b c cos A+c ...

Question

2(bc cos A+ ca cos B + ab cos C)=

abc

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2abc

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a²+b²+c²

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a²+b²-c²

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Solution

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Similar questions

$2 (b c c o s A + c a c o s B + a b c o s C) = a^{2} + b^{2} + c^{2}$

a b c

a + b + c

a^{2} + b^{2} + c^{2}

\frac{1}{a^{2}} + \frac{1}{b^{2}} + \frac{1}{c^{2}}

A B C

2 (b c cos A + c a cos B + a b cos C) = a^{2} + b^{2} + c^{2}

Mark the correct alternative in each of the following :

$I n a n y Δ A B C, 2 (b c c o s A + c a c o s B + a b c o s C) =$

2 (b c \cos A + c a \cos B + a b \cos C) = a^{2} + b^{2} + c^{2}

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