2-Bromo-3-phenylpropane can be synthesized by:

C_{6} H_{5} C H_{2} C H (O H) C H_{3} + P B r_{3} \to

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C_{6} H_{5} C H = C H C H_{3} + H B r + b e n z o y l p e r o x i d e \to

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C_{6} H_{5} C H_{2} C H_{2} C H_{3} + B r_{2} + l i g h t \to

No worries! We‘ve got your back. Try BYJU‘S free classes today!

none of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct options are
A $C_{6} H_{5} C H_{2} C H (O H) C H_{3} + P B r_{3} \to$
C $C_{6} H_{5} C H = C H C H_{3} + H B r + b e n z o y l p e r o x i d e \to$
2-Bromo-3-phenylpropane can be synthesized by reactions A and
B. In reaction A, -OH group is replaced with Br.
(A) $C_{6} H_{5} C H_{2} C H (O H) C H_{3} + P B r_{3} \to C_{6} H_{5} C H_{2} C H (B r) C H_{3}$
In the reaction B, a molecule of HBr is added across C=C bond.
(B) $C_{6} H_{5} C H = C H C H_{3} + H B r + b e n z o y l p e r o x i d e \to C_{6} H_{5} C H_{2} C H (B r) C H_{3}$
In the reaction C, 1-Bromo-1-phenylpropane is obtained.
(C) $C_{6} H_{5} C H_{2} C H_{2} C H_{3} + B r_{2} + l i g h t \to C_{6} H_{5} C H B r C H_{2} C H_{3}$

Suggest Corrections

Similar questions

The reaction of $C_{6} H_{5} C H = C H C H_{3}$ with HBr produces :

B r_{2}

H_{2} + B r_{2} \to 2 H B r

{C H}_{3} C H = C H {C H}_{3} + {B r}_{2} \to

H_{2}

B r_{2}

H B r

B r_{2}

B r

B r_{2}

E = 1240

Join BYJU'S Learning Program