2-Bromopentane is heated with potassium ethoxide in ethanol. The major product obtained is

2-Ethoxypentane

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Pent-1-ene

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Cis-pent-2-ene

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Trans-pent-2-ene

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Solution

The correct option is D Trans-pent-2-ene
$E_{1}$ reaction is a two step process.
In step 1, leaving group leaves and form a carbocation.
In step 2, the base will attack the proton and proton abstraction takes place to form alkenes.
The major product will be the alkene which has more substitution by Saytzeff rule. Since, it gives the stable alkene.

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