$2 C_{6} H_{5} C H O + {O H}^{-} ⟶ C_{6} H_{5} C O O^{-} + C_{6} H_{5} {C H}_{2} O H$

The above reaction is disproportionation reaction.
State whether the statement is true or false?

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Solution

$2 C_{6} H_{5} C H O + {O H}^{-} ⟶ C_{6} H_{5} C O O^{-} + C_{6} H_{5} {C H}_{2} O H$
In given reaction,
$C_{6} H_{5} C H O$ is oxidised to $C_{6} H_{5} C O O^{-}$ as well as reduced to $C_{6} H_{5} {C H}_{2} O H$ (Canizzaro reaction).

Hence, the reaction is a disproportionation reaction. Therefore above statement is true.

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Similar questions

A : 2 C_{6} H_{5} C H O + K O H ⟶ C_{6} H_{5} C O O K + C_{6} H_{5} {C H}_{2} O H

B : 3 {C l}_{2} + 6 K O H ⟶ 5 K C l + K C l O_{3} + 3 H_{2} O

C_{6} H_{6} \to C_{6} H_{5} {C H}_{3}

\begin{matrix} O H | C H_{3} - & C - & C_{6} H_{5} | C_{2} H_{5} \end{matrix}

C_{6} H_{5} C H O + C H_{3} C O C H_{3} O H^{-} - -------- \to Δ P

{C H}_{3} - O - C_{6} H_{4} O H

C_{6} H_{5} - O H

{N O}_{2} - C_{6} H_{4} O H

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