$2 C a_{3} (P O_{4})_{2} + 6 S i O_{2} + 10 C \to P_{4} + C a S i O_{3} + 10 C O$
Find the coefficient on the right hand side for $C a S i O_{3}$ which balance the reaction given above?

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Solution

The correct option is C 6
The coefficient $6$ on the right-hand side for $C a S i O_{3}$ balances the reaction given above.
On LHS, we have $6 C a$ atoms. To balance these, we need $6 C a$ atoms on RHS.

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2 C a_{3} (P O_{4})_{2} + 6 S i O_{2} + 10 C \to P_{4} + . . . C a S i O_{3} + 10 C O

2 C a_{3} (P O_{4})_{2} + 6 S i O_{2} + 10 C \to P_{4} +

C a S i O_{3} + 10 C O

2 {C a}_{3} {(P O_{4})}_{2} + 6 S i O_{2} + 10 C \to P_{4} +__C a S i O_{3} + 10 C O

C a_{3} (P O_{4})_{2} + S i O_{2} + C \to C a S i O_{3} + P_{4} + C O

C a O (s) + S i O_{2} (s) \to C a S i O_{3} (s)

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