Question

$2-Chlorobutane\underset{}{\overset{15percentaq.solutionofethylalcohol}{\to }}P$
In this reaction 70% racemization takes place. % of the inverted product would be:

• A. $30$
• B. $70$
• C. $35$
• D. $65$

Answer 1

Answer: (C)

$35$

In above reaction $-OH$ is substituted at $2^{\circ }$ carbon so racemization occurs. If 100% racemization occurs the compound would be 50% inverted 50% retention.

So for 70% racemization 35% would be inverted.