2 cos 3 theta =root 3 find the value of theta

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If $\sqrt{3} sin θ = cos θ$ , find the value of $\frac{3 {cos}^{2} θ + 2 cos θ}{3 cos θ + 2}$

3 cot θ = 2

\frac{2 sin θ - 3 cos θ}{2 sin θ + 3 cos θ}

\frac{s i n θ - 2 s i n^{3} θ}{2 c o s^{3} θ - c o s θ}

sin θ + {sin}^{2} θ = 1,

{cos}^{12} θ + 3 {cos}^{10} θ + 3 {cos}^{8} θ + {cos}^{6} θ + 2 {cos}^{4} θ + 2 {cos}^{2} θ - 2

cot θ

\frac{4 sin θ - 3 cos θ}{2 sin θ + 6 cos θ}

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