Question

2 cubes each of volume 64 $c{m}^3$ are joined end to end. Find the surface area of the resulting cuboid (in $c{m}^2$)

__

Answer 1

Let l be length of each cube
Volume of each cube = $l^3$ =64 $c{m}^3$

$\Rightarrow$ $l^3=64c{m}^3$

$\Rightarrow$ l = 4 cm
If, we join 2 cubes each having side equal to 4 cm, we get a cuboid

Length of cuboid= L=8 cm

Height of cuboid=H=4 cm

Breadth of cuboid=B=4 cm
cm
We know that Surface Area of Cuboid =2(L.B+B.H+H.L)= 2((8x4)+(4x4)+(4x8))

=2(32+16+32)

= 2(80)

=160 $c{m}^2$