Question

2 cubes each of volume $64$ $c{m}^3$ are joined end to end. Find the surface area of the resulting cuboid.

Answer 1

If measurement of each side of each cube be I cm, then
$(I{)}^3=\sqrt[3]{364}$
$\therefore I=4$ cm
Length of cubes if joined together,
Length, I = 4 + 4 = 8 cm.
Breadth, b = 4 cm
Height, h = 4 cm
Surface area of the cuboid,
= 2Ib + 2Ih + 2bh
= 2(8 x 4) + 2(8 x 4) + 2(4 x 4)
= 2 x 32 + 2 x 32 + 2 x 16 = 64 + 64 + 32
= 160 sq.cm.