Question

$2$ cubes each of volume $64{cm}^3$ are joined end to end. Find the surface area of the resulting cuboid.

• A. $110c{m}^2$
• B. $100c{m}^2$
• C. $260c{m}^2$
• D. $160c{m}^2$

Answer 1

Answer: (D)

$160c{m}^2$

length of cube = a

$a^3=64$

$\Rightarrow a=4$

Length of cuboid = $8=l$

breadth of cuboid = $4=b$

height of cuboid = $4=h$

Ref. image

Surface area $\Rightarrow 2(lb+bh+lh)$

$=2\left(\right(8\times 4)+(4\times 4)+(8\times 4\left)\right)$

$=2(32+16+32)$

$=160c{m}^2$