Question

$2$ cubes each of volume $64c{m}^3$ are joined end to end. Find the surface area of the resulting cuboids.

Answer 1

Given that,

Volume of each cube $=64c{m}^3$

$(Edge{)}^3=64$

$Edge=\sqrt[3]{364}=\sqrt[3]{34\times 4\times 4}=4cm$

If cubes are joined end to end, the dimensions of the resulting cuboid will be 4 cm, 4 cm, 8 cm.

i.e, $Length,l=4cm,breadth,b=4cm,$ and $height,h=8cm$

$\therefore$ Surface area of the resulting cuboid $=2(lb+bh+lh)$

$=2\left[\right(4\times 4)+(4\times 8)+(4\times 8\left)\right]$

$=2(16+32+32)$

$=2(16+64)$

$=2\times 80=160c{m}^2$