Question

$2\frac{3}{4}+1\frac{2}{3}=$ $4\frac{x}{12}$. Find x.

Answer 1

We have

$2\frac{2}{3}+1\frac{2}{3}=4\frac{x}{12}$

$\Rightarrow \frac{8}{3}+\frac{5}{3}=\frac{48+x}{12}$

$\Rightarrow \frac{8+5}{3}=\frac{48+x}{12}\left[L.C.Mof3\&3=3\right]$

$\Rightarrow \frac{13}{3}=\frac{48+x}{3}$

$\Rightarrow 48+x=\frac{13\times 12}{3}$

$\Rightarrow 48+x=52\left[divide12by3weget4\right]$

$\Rightarrow x=52-48$

$\therefore x=4$

Hence the value of $x=4$