2 equal charges are kept at a certain distance from each other. The force on one of the charges is measured to be F. If the magnitude of one of the charge is increased by a factor of 3, what is the magnitude of the new force felt by the first charge?

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

F/3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

F/9

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
3F

In the coulomb’s law, the electrostatic force is directly proportional to the product of charges,

$F \propto q_{1} q_{2}$

$∴ \frac{F_{1}}{F_{2}} \frac{q \times q}{q \times 3 q}$

$F_{2} = 3 F$

Suggest Corrections

Similar questions

Two charges of unknown magnitudes are kept 5m away from each other. The magnitude of force between them is measured to be F. If these charges are then moved so that the distance between them is 20m, what is the new force between them?

Q. A positive charge q exerts a force of magnitude - 0.2 N on another charge, which has a magnitude twice as the other charge. Find the magnitude of each charge if the distance separating them is equal to 50 cm. (Ans = 1.66 × 10-6 C)

Q. Two point charges repel each other with a force of

100 N

. One of the charges is increased by

10 %

and the other is reduced by

10 %

. The new force of repulsion at the same distance would be

The charge of one of two small charged sphere conductor is twice of the other. the two conductor repel each other with a force of 50dyn. if their distance is redued by 3cm the force becomes 50dyn. what is the magnitude of their charges and what was the initial distance?

Join BYJU'S Learning Program

2 equal charges are kept at a certain distance from each other. The force on one of the charges is measured to be F. If the magnitude of one of the charge is increased by a factor of 3, what is the magnitude of the new force felt by the first charge?

The correct option is B 3F In the coulomb’s law, the electrostatic force is directly proportional to the product of charges, F∝q1q2 ∴F1F2q×qq×3q F2=3F

The correct option is B
3F

In the coulomb’s law, the electrostatic force is directly proportional to the product of charges,

$F \propto q_{1} q_{2}$

$∴ \frac{F_{1}}{F_{2}} \frac{q \times q}{q \times 3 q}$

$F_{2} = 3 F$