Question

2-Ethoxy-2-methylpropane when reacted with HI, products obtained are

• A. Iodoethane and 2-Methylpropan-2-ol
• B. Iodoethane and 2-methylpropene
• C. 2-Iodo-2-methylpropane and ethanol
• D. ethene $\&$ 2-Iodo-2-methylpropane

Answer 1

The correct option is C 2-Iodo-2-methylpropane and ethanol

In step 2 of the reaction, the departure of leaving group $(HO–C_2{H}_5)$ creates a more stable carbocation $\left[\right(C{H}_3{)}_3{C}^{+}]$, and the reaction follows $S{N}_1$ mechanism.