Question

$2\frac{6}{7}+10-\frac{7}{5}=?$

• A. $12\frac{14}{35}$
• B. $11\frac{16}{35}$
• C. $11\frac{14}{35}$
• D. $12\frac{16}{35}$

Answer 1

The correct option is B

$11\frac{16}{35}$

$2\frac{6}{7}+10-\frac{7}{5}$
Firstly, convert mixed fraction into improper fraction.
$2\frac{6}{7}$ $=\frac{(7\times 2)+6}{7}=\frac{20}{7}$

Now the questions is reduced to $\frac{20}{7}+10-\frac{7}{5}$.

LCM of 7 and 5 is 35 as they are prime numbers, we can just multiply the two numbers.

$\frac{20}{7}+10-\frac{7}{5}$ $=\frac{20\times 5}{7\times 5}+\frac{10\times 35}{1\times 35}-\frac{7\times 7}{5\times 7}=\frac{100}{35}+\frac{350}{35}-\frac{49}{35}=\frac{100+350-49}{35}=\frac{450-49}{35}=\frac{401}{35}=11\frac{16}{35}$