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Atomicity

2 g of acetat...

Question

2 g of acetate ion in form of sodium acetate is added to $500 m L$ of a solution of $0.10 M$ acetic acid $p K a (C H_{3} C O O H) = 4.74$ $p H$ of solution is $(l o g 6 = 0.778)$

5.01

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5.70

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4.57

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4.74

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Solution

The correct option is C $4.57$
For acidic buffer
$p H = p K_{a} + l o g \frac{[s a l t]}{[a c i d]}$
$= 4.74 + l o g$ $\frac{[\frac{2}{59} \times \frac{1000}{500}]}{0.1}$
$= 4.74 + l o g \frac{40}{59}$
$= 4.74 - 0.1739$
$= 4.57$

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2 g

500 mL

0.10 M

p K_{a} (C H_{3} C O O H) = 4.74

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2 g

500 mL

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p K_{a} (C H_{3} C O O H) = 4.74

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H C l

\frac{1}{2} mL

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[p K_{a} (C H_{3} C O O H) = 4.74]

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