2 $g$ of $H_{2}$ and 32 $g$ of $O_{2}$ at $N T P$ occupy a volume of $c c$ :

44800

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22400

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11200

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5600

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Solution

The correct option is D $44800$
We have $1$ mole of $H_{2}$ and $1$ mole of $O_{2}$ at $N T P$ .
Thus, each gas will occupy $22.4$ litres at $N T P$ .
Total volume occupied by two gases = $44.8$ litres = $44800 c c$

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