$2$ g of hydrogen diffuses from a container in $10$ minutes . How many grams of oxygen would diffuse through the same container in the same time under similiar conditions ?

0.5 g m

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1 g m

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2 g m

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8 g m

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Solution

The correct option is D $8 g m$
$\frac{r_{H_{2}}}{r_{O_{2}}} = \frac{V_{H_{2}}}{V_{O_{2}}}$
$\frac{n_{H_{2}}}{n_{O_{2}}} = \sqrt{\frac{M_{O_{2}}}{M_{H_{2}}}}$
$\Rightarrow \frac{\frac{2}{2}}{\frac{w}{2}} = \sqrt{\frac{32}{2}} = \sqrt{16} = 4$
$\Rightarrow \frac{32}{w} = 4$
$\Rightarrow w = 8$ gms

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2g of hydrogen diffuses from a container in 10 minutes . How many grams of oxygen would diffuse through the same container in the same time under similiar conditions ?

The correct option is D 8 gmrH2rO2=VH2VO2nH2nO2=√MO2MH2⇒22w2=√322=√16=4⇒32w=4⇒w=8gms

$2$ g of hydrogen diffuses from a container in $10$ minutes . How many grams of oxygen would diffuse through the same container in the same time under similiar conditions ?

The correct option is D $8 g m$
$\frac{r_{H_{2}}}{r_{O_{2}}} = \frac{V_{H_{2}}}{V_{O_{2}}}$
$\frac{n_{H_{2}}}{n_{O_{2}}} = \sqrt{\frac{M_{O_{2}}}{M_{H_{2}}}}$
$\Rightarrow \frac{\frac{2}{2}}{\frac{w}{2}} = \sqrt{\frac{32}{2}} = \sqrt{16} = 4$
$\Rightarrow \frac{32}{w} = 4$
$\Rightarrow w = 8$ gms