Question

2 g of hydrogen is sealed in a vessel of volume 0.02 m³ and is maintained at 300 K. Calculate the pressure in the vessel.

Answer 1

Given:
Mass of hydrogen, m = 2 g
Volume of the vessel, V = 0.02 m³
Temperature in the vessel, T = 300 K
Molecular mass of the hydrogen, M = 2 u

No of moles, n = $\frac{m}{M}=\frac{2}{2}$= 1 mole

Rydberg's constant, R = 8.3 J/Kmol

From the ideal gas equation, we get

PV = nRT
$$\begin{gathered} \Rightarrow P=\frac{nRT}{V} \\ \Rightarrow P=\frac{1\times 8.3\times 300}{0.02} \end{gathered}$$
$\Rightarrow$P = 1.24 × 10⁵ Pa