$2 g$ of hydrogen will have same number of molecules as is present in:

14 g

of nitrogen

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32 g

of sulphur dioxide

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71 g

of chlorine

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24 g

of ozone

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Solution

The correct option is C $71 g$ of chlorine
$N_{A}$ molecules are present in $1$ mole of hydrogen i.e $1 g$ of hydrogen.
So, $2 g$ of hydrogen has $2 N_{A}$ molecules
Similarly, $71 g$ of chlorine is $(2 \times 35.5 g)$ i.e $2$ moles of chlorine.
So, $2$ moles of chlorine will also have $2 N_{A}$ molecules.
On the other hand, $14 g$ of $N$ has $N_{A}$ molecules
$32 g$ of $S O_{2}$ has $N_{A} / 2$ molecules
$24 g$ of $O_{3}$ has $N_{A} / 2$ molecules

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Similar questions

Under the same conditions of temperature and pressure you collect 2 litres of carbon dioxide, 3 litres of chlorine, 5 litres of hydrogen, 4 litres of nitrogen and 1 litre of sulphur dioxide. In which gas sample will there be:
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(b) The least number of molecules.
Justify your answer.

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Deduce the number of molecules of the following compounds in the given quantities.

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Q. 2 g of hydrogen will have same number of molecules as is present in:

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2g of hydrogen will have same number of molecules as is present in:

$2 g$ of hydrogen will have same number of molecules as is present in: