Question

2 g of oxygen contains number of atoms equal to that in:

• A. 20 g of hydrogen
• B. 4 g of sulphur
• C. 7 g of nitrogen
• D. 2.3 g of sodium

Answer 1

The correct option is B 4 g of sulphur

Oxygen $\Rightarrow$ molar mass = 16g =1 mole of $O_2$

Then, $2g$ of oxygen $=\frac{2}{16}$ moles of $O_2$

Solphur $\Rightarrow$ Molar mass =32 g = 1 mole of sulphur.

Then $4g$ of sulphur =$\frac{4}{32}\times 1$ mole of sulphur.

0.125 ,moles of oxygen and 0.125 mole of sulphur contains same number of atoms as 1 mole of any gashas $6.023\times {10}^{23}$ atoms.