$2 g$ of oxygen contains number of atoms to that in:

0.5 g

of hydrogen

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4 g

of sulphur

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7 g

of nitrogen

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2.3 g

of sodium

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Solution

The correct option is A $4 g$ of sulphur
No. of moles in $2 g$ of Oxygen $= \frac{2}{16} = \frac{1}{8} m o l e$
No. of atoms of $O = \frac{1}{8} \times N a a t o m s$ Here $N a$ is the Avogadro's number
No. of moles in $4 g$ of Sulphur $= \frac{4}{32} = \frac{1}{8} m o l e$
No. of atom of S $= \frac{1}{8} \times N a$ atoms
Thus, $4 g$ of sulphur contains equal atoms to that of $2 g$ of $O$ atoms.
Hence, option $B$ is correct.

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