Question

2 girls and 4 boys are to be seated in a row in such a way that the girls do not sit together. In how many different ways can it be done?

• A. 720
• B. 480
• C. 360
• D. 240
• E. None of these

Answer 1

The correct option is B 480

4 boys can be seated in a row in ${}^4{P}_4$ = 4! ways.
Now, in the 5 gaps, 2 girls can be arranged in ${}^5{P}_2$ ways.
Hence, the number of ways in which no two girls sit together
$=4!\times {}^5{P}_2=4\times 3\times 2\times 5\times 4=480$