2 gm of oxygen contains number of atoms equal to that in:

0.5 gm of hydrogen

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 gm of sulphur

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

7 gm of nitrogen

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.3 gm of sodium

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 4 gm of sulphur
moles of orygen $\frac{2 (g i v e n)}{16}$ $= 0.124$
moles of hydrogen $= \frac{0.5}{1} = 0.5$
moles of sulphur $= \frac{4}{32} = 0.125$
moles of nitrogen $= \frac{7}{14} = 0.5$
moles of sodium $= \frac{2.3}{23} = 0.1$
moles of oxygen $=$ moles of sulphur $(4 g m)$
Hence, the correct option is $B$

Suggest Corrections

Similar questions

34 gm of $H_{2} O$ is decomposed to form _______ gm of hydrogen and ____ gm of oxygen.

When decomposed, 36 gm of $H_{2} O$ gives _______ g of hydrogen and ____ g of oxygen.

34 g of $H_{2} O$ decomposes to _______ g of hydrogen and ____ g of oxygen.

1.61

N a_{2} S O_{4} .10 H_{2} O

x

H_{2} S O_{4.}

x

{S O}_{3}

μ

μ

μ

Join BYJU'S Learning Program