$2 H_{3} C - C O O A g I_{2} - -- \to C C l_{4} P (a n e s t e r) + C O_{2} + A g I$
Which of the following reactions will also give the same product P?

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Solution

The correct option is B
P is $C H_{3} C O O C H_{3}$ .

Of the given options, only b will give the required product via Baeyer-Villiger oxidation.

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2 H_{3} C - C O O A g I_{2} - -- \to C C l_{4} P (a n e s t e r) + C O_{2} + A g I

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