2. In a triangle ABC, prove that AB+BC+AC>2AB

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In triangle ABC prove AB+BC+CA >2AB

. O is any point in the interior of a triangle ABC. Prove that

1. AB + AC > OB + OC

2.AB + BC + CA > OA + OB + OC

3.OA + OB + OC > 1/2(AB + AC + BC)

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∠ A = 60

{B C}^{2} = {A B}^{2} + {A C}^{2} - A B \cdot A C

△ A B C, ∠ A B C = 135^{o}

A C^{2} = A B^{2} + B C^{2} + 4 A (△ A B C)

ABC is an isosceles triangle with AC = BC. If AB² = 2 AC², prove that ABC is a right triangle.

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