2 is a polynomial of degreea 2b 0c 1d 12

Given: nbsp;f(x) = nbsp;2 It can also be written as nbsp;fx=2x0. Degree is the highest power of nbsp;x nbsp;in the polynomial. Here, the highest pow ...

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Standard IX

Mathematics

Degree of the Polynomial

2 is a polyno...

Question

$\sqrt{2}$ is a polynomial of degree
(a) 2
(b) 0
(c) 1
(d) $\frac{1}{2}$

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Solution

Given: f(x) = $\sqrt{2}$
It can also be written as $f (x) = \sqrt{2} x^{0}$ .

Degree is the highest power of x in the polynomial.

Here, the highest power of x is 0.

Thus, degree of the polynomial is 0.

Hence, the correct option is (b).

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Q. Let

f (x)

be a polynomial of degree

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satisfying

f (0) = 1,

f'(0)=-2

a n d f^{''} (0) = 6,

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Q. Let P(x) be a polynomial of degree 4, with

P (2) = - 1

P^{'} (2) = 0

P^{''} (2) = 2

P^{'''} (2) = - 12

and

P^{i v} (2) = 24

, The value of

P^{''} (1)

Let $P (x)$ be a polynomial of degree 4, with $P (2) = 1,$ $P^{'} (2) = P^{''} (2) = 0$ , $P^{'''} (2) = 12$ and $P^{''''} (2) = 24$ . Then the value of $P^{''} (1)$ is

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2 is a polynomial of degree (a) 2 (b) 0 (c) 1 (d) 12

Given: f(x) = 2 It can also be written as fx=2x0. Degree is the highest power of x in the polynomial. Here, the highest power of x is 0. Thus, degree of the polynomial is 0. Hence, the correct option is (b).

$\sqrt{2}$ is a polynomial of degree
(a) 2
(b) 0
(c) 1
(d) $\frac{1}{2}$

Given: f(x) = $\sqrt{2}$
It can also be written as $f (x) = \sqrt{2} x^{0}$ .

Degree is the highest power of x in the polynomial.

Here, the highest power of x is 0.

Thus, degree of the polynomial is 0.

Hence, the correct option is (b).