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Question

2km wide river flowing at the rate 5km/hr. A man can swim is still water 10km/hr. He wants to cross the river along the shorted path. Find-
(a) in which direction should the person swim.
(b) crossing time.

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Solution

Since the man goes along the shortest path.
So, 10cosθ=5
cosθ=12
θ=60o from opposite to flow
or θ=18060 from flow
=120o
Time taken =distancespeed=210sin60
=15×32
=252

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