An electric discharge is passed through a mixture containing 50 cc of $O_{2}$ and 50 cc of $H_{2}$ . The volume of the gas formed (i) at room temperature (ii) at $110^{\circ} C$ will be:

(All measurements are made at same pressure and temperature)

Q. The process of eudiometry is used to calculate the volume of the various reacting gases present in a closed vessel. A spark is made and the change in volume or pressure is noted depending on the conditions mentioned. Various reagents like alkaline pyrogallol, turpentine oil, caustic potash, conc.

H_{2} S O_{4}

are used to absorb the selective gases like

O_{2}, O_{3}, C O_{2}

and

H_{2} O

(v) respectively.
A 4.0 mole mixture of

H_{2} (g), O_{2} (g)

and He(g) are placed in a closed container at a pressure of 50 atm. An electric spark is passed, the pressure is noted to be 12.5 atm after cooling the contents to the room temperature. Oxygen gas is introduced to increase the pressure to 25 atm, keeping volume and the temperature constant. Again, an electrical spark is passed, and the pressure drops to 10 atm at room temperature conditions. List-I contains questions and List-II contains their answers.

List- IList-II(I)What is the mole fraction of H2(g)present(P)0.6in the initial mixture?(II)How many moles of He(g) are present in the sample?(Q)1.0(III)How many moles of oxygen remain in the final gaseous(R)0.8mixture that is left?(IV)How many moles of O2(g) are introduced in the vessel (S)0.2after the first electrical spark? (T)0.7(U)0.4

Which of the following options has the correct combination considering List-I and List-II

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2 L of H2 and 2L of O2 are mixed at 10oC and 1atm. An electric spark is passed through the mixture, upon which there is 'pop'. On bringing back the temperature and pressure to the original values, will there be any gas(es) left? If the answer is yes, what will be their volumes?

2H2+O2⟶2H2Omole:2×0.0430.0432×0.0432 litre of H2 and O2 at 10℃ and 1 atm pressure,n=2litre×1atm0.0821lit−atmmol−1K−1×283K∴nO2=0.043 gas left∴VO2=0.043mole×0.0821lit−atmmol−1K−1×283K1atm=0.999≈1L of O2 gas is left.

2 L of H $_{2}$ and 2L of O $_{2}$ are mixed at 10 $^{o}$ C and 1atm. An electric spark is passed through the mixture, upon which there is 'pop'. On bringing back the temperature and pressure to the original values, will there be any gas(es) left? If the answer is yes, what will be their volumes?