2 lines originating from a point P intersects a circle at 4 points as shown in the figure.Given AB=5,AP=2,PC=1; what is the length of CD.

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Solution

The correct option is D
13

From the results of Power of a point theorem as we have seen from the previous problem,

$P B \times P A$ = $P D \times P C$

$(2 + 5) \times 2 = (C D + 1) \times 1$

$14 = C D + 1$

$C D = 13$

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2 lines originating from a point P intersects a circle at 4 points as shown in the figure.Given AB=5,AP=2,PC=1; what is the length of CD.

The correct option is D 13 From the results of Power of a point theorem as we have seen from the previous problem, PB×PA =PD×PC (2+5)×2=(CD+1)×1 14=CD+1 CD=13

The correct option is D
13

From the results of Power of a point theorem as we have seen from the previous problem,

$P B \times P A$ = $P D \times P C$

$(2 + 5) \times 2 = (C D + 1) \times 1$

$14 = C D + 1$

$C D = 13$