2 litres of a gas is enclosed in a vessel at a pressure of 760 mm Hg. If tempreature remains constant, calculate pressure when volume changes to 4 $d m^{3}$

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Solution

When temperature is constant, then the Boyle's law comes into play.
P₁V₁=P₂V₂
=760 mm Hg
=2L
=4 = 4L
$P subscript 2 equals fraction numerator P subscript 1 V subscript 1 over denominator V subscript 2 end fraction equals fraction numerator 760 cross times 2 over denominator 4 end fraction equals 380 space m m space o f space H g$

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2 litres of a gas is enclosed in a vessel at a pressure of 760 mm Hg. If tempreature remains constant, calculate pressure when volume changes to 4 dm3

When temperature is constant, then the Boyle's law comes into play. P1V1=P2V2 =760 mm Hg =2L =4 = 4L

2 litres of a gas is enclosed in a vessel at a pressure of 760 mm Hg. If tempreature remains constant, calculate pressure when volume changes to 4 $d m^{3}$